Date: Tue, 1 Dec 1998 00:46:52 +0000 From: Ben Smithurst <ben@scientia.demon.co.uk> To: Chris <chrisj@outcast.media-net.net> Cc: freebsd-questions@FreeBSD.ORG Subject: Re: umask Message-ID: <19981201004652.A23208@scientia.demon.co.uk> In-Reply-To: <Pine.BSF.3.96.981130183801.9430A-100000@outcast.media-net.net> References: <Pine.BSF.3.96.981130183801.9430A-100000@outcast.media-net.net>
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Chris wrote: > hello. i was wondering if someone could please explain the working of > umask. i understand what it does and what not By this, I assume you mean that with umask of 022, normal files will be created with mode 0666 with 022 masked out, = 0644 ? > just not how to work out the octal numbers to get the desired result. chmod(1) explains it quite well. Basically, 0400 - owner read 0200 - owner write 0100 - owner exec 0040 \ 0020 - as above but for group 0010 / 0004 \ 0002 - as above but for world 0001 / -- Ben Smithurst ben@scientia.demon.co.uk send a blank message to ben+pgp@scientia.demon.co.uk for PGP key To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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