From owner-freebsd-current Sun Mar 25 0:33:28 2001 Delivered-To: freebsd-current@freebsd.org Received: from leviathan.inethouston.net (216-118-21-146.pdq.net [216.118.21.146]) by hub.freebsd.org (Postfix) with ESMTP id 26B7537B71A for ; Sun, 25 Mar 2001 00:33:27 -0800 (PST) (envelope-from dwcjr@inethouston.net) Received: from dwcjr (216-118-21-147.pdq.net [216.118.21.147]) by leviathan.inethouston.net (Postfix) with ESMTP id BDE23111337; Sun, 25 Mar 2001 02:33:32 -0600 (CST) Message-ID: <01ef01c0b506$44825fc0$931576d8@inethouston.net> From: "David W. Chapman Jr." To: "Leif Neland" , References: Subject: Re: /etc/exports: 192.168.5 = 192.168.0.5 Date: Sun, 25 Mar 2001 02:33:28 -0600 MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.50.4522.1200 X-MimeOLE: Produced By Microsoft MimeOLE V5.50.4522.1200 Sender: owner-freebsd-current@FreeBSD.ORG Precedence: bulk X-Loop: FreeBSD.ORG From a pure logic point of view here's something that might help you understand it the 4 octets are broken down into binary and then combined without the decimal point. when whatever libraries are doing this, the first octec(192) is converted to binary. Then there is probably some sort of if statement that says if there is only one more octet to process make it the last octet. The reason for this is so you can enter in ip addresses like 3232236800 which is another way of looking at 192.168.5.0, if it wasn't processed like this, it might try to ping 3232236800.0.0.0 If I've caused any more confusion than help, let me know and I can email you in private and help better explain. To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-current" in the body of the message