Date: Fri, 10 Aug 2001 10:54:13 -0400 From: Mike Smith <mlsmith@mitre.org> To: Rob <europax@home.com> Cc: "hackers@FreeBSD.ORG" <hackers@freebsd.org> Subject: Re: the =+ operator Message-ID: <3B73F595.CD12F8AA@mitre.org> References: <3B73F0BC.548D40B3@home.com>
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I've been doing this for a long time and today this would be taken as two operators. The assignment and unary +. Since A = B is the same as A = +B, it would perform the same as a simple assignment. The only reason I can see to do this legitimately is for clarity reasons, i.e., if what follows the "+" is almost always used as a negative but this use is an exception. But more likely, at some point there was something between the = and + at one point that got deleted, but the "+" was left. Since this is "the default", there would be no coding or operational errors from leaving it in. Then again, it could have been intended to be += and you've found a heretofore undiscovered bug! All you have to do is press Shift at the wrong time (not that I've ever done that). Mike Smith (but not "THE" Mike Smith) Rob wrote: > > My first post on hackers, so please don't flame me too bad :) I think > that only an old hacker can give me the answer :) > > I've searched far and wide on search engines to find out what the =+ > operator does, to no avail. I'm porting some old code and found it. I > made a test program and compiled it with gcc, and all it appears to do > is the same as regular assignment. But I'm wondering if in some day > long ago, it mean't something else? Thanks, Rob. > > To Unsubscribe: send mail to majordomo@FreeBSD.org > with "unsubscribe freebsd-hackers" in the body of the message To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-hackers" in the body of the message
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