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Date:      Mon, 20 Nov 2000 17:58:39 +0200
From:      Peter Pentchev <roam@orbitel.bg>
To:        Alex Koshterek <havoc@lookanswer.com>
Cc:        Thomas Moestl <tmoestl@gmx.net>, freebsd-hackers@FreeBSD.ORG
Subject:   Re: Byte order?
Message-ID:  <20001120175839.B6292@ringworld.oblivion.bg>
In-Reply-To: <00112017513301.47740@pro.lookanswer.com>; from havoc@lookanswer.com on Mon, Nov 20, 2000 at 05:47:47PM %2B0200
References:  <00112017175200.47740@pro.lookanswer.com> <20001120164006.A1624@crow.dom2ip.de> <00112017513301.47740@pro.lookanswer.com>

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On Mon, Nov 20, 2000 at 05:47:47PM +0200, Alex Koshterek wrote:
> > This program gets it wrong. When the last byte of a long is set after the long was
> > set to 1, we have a big endian architecture (the "little" end is at the 4th byte,
> > so the "big end" is at the 1st byte).
> > The x86 architecture _is_ little endian.
> > 
> What? 
> on x86  long a =1
> in memory is a  01 00 00 00
> Lesser significant byte is first and most significant is last

Exactly - the least significant byte comes first, the number is stored
in memory from its 'little' end towards its 'big' end - hence, little-endian.

G'luck,
Peter

-- 
I am not the subject of this sentence.


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