Date: Sat, 18 Mar 2000 10:46:49 +0530 (IST) From: Rahul Siddharthan <rsidd@physics.iisc.ernet.in> To: Kris Kennaway <kris@hub.freebsd.org> Cc: Brett Taylor <brett@peloton.runet.edu>, Mark Ovens <mark@dogma.freebsd-uk.eu.org>, Paul Richards <paul@originative.co.uk>, chat@FreeBSD.ORG Subject: Re: Useful Metric Conversions Message-ID: <Pine.LNX.4.20.0003181040030.574-100000@theory8.physics.iisc.ernet.in> In-Reply-To: <Pine.BSF.4.21.0003171228110.47816-100000@hub.freebsd.org>
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> > I'll stick w/ mass - at least I'll buy the same amount on each planet or > > in an accelerating frame. :-) > > I think you meant 'inertial frame'. In an accelerating frame your inertial > mass (and gravitational mass, by the equivalence principle) will be > different. No, your mass is the same, your weight changes. You are weightless in a freely falling elevator, but certainly not massless. The definition of "inertial frame" or "accelerated frame" varies: traditionally, earth's surface is (nearly) an inertial frame with an external force (Earth's gravity) and the freely falling elevator would be an accelerated frame and the acceleration would give rise to a pseudoforce which cancels your weight due to Earth's gravity; but in general relativity the elevator is an inertial frame, not earth's surface, and your weight on earth's surface (which you attribute to "gravity") is really a pseudoforce arising from your being in an accelerated frame. > The moral of the story: buy your sugar in a freely-falling elevator car. If you only want to lose weight, of course, the freely falling elevator (or an orbiting satellite, etc) is the place to be. To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-chat" in the body of the message
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