From owner-freebsd-hackers Fri Feb 16 02:45:22 1996 Return-Path: owner-hackers Received: (from root@localhost) by freefall.freebsd.org (8.7.3/8.7.3) id CAA26960 for hackers-outgoing; Fri, 16 Feb 1996 02:45:22 -0800 (PST) Received: from haldjas.folklore.ee (Haldjas.folklore.ee [193.40.6.121]) by freefall.freebsd.org (8.7.3/8.7.3) with SMTP id CAA26893 for ; Fri, 16 Feb 1996 02:44:33 -0800 (PST) Received: (from narvi@localhost) by haldjas.folklore.ee (8.6.12/8.6.12) id MAA13884; Fri, 16 Feb 1996 12:46:50 +0200 Date: Fri, 16 Feb 1996 12:46:49 +0200 (EET) From: Narvi To: Nate Williams cc: hackers@FreeBSD.ORG Subject: Re: Broadcast, Netmask, and other such information In-Reply-To: <199602152223.PAA01710@rocky.sri.MT.net> Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Sender: owner-hackers@FreeBSD.ORG Precedence: bulk On Thu, 15 Feb 1996, Nate Williams wrote: > David Greenman writes: > > >Maybe I'm not making myself clear. When I say 'addresses in the > > >subnet', I'm trying to convey a number which *should* be a power of 2 #. > > >In the above example, there are 32 addresses assigned in each subnet, of > > >which there are only 31 usable as host addresses (except in the first > > >and last subnets due to the .0 & .255 addresses being unusable). > > > > Actually, no, you would only get 30 hosts per subnet. The all-ones host > > part on each subnet is the subnet's broadcast address and all-zeros host > > can't be used, either. > > I'm assigned 32 IP addresses out of the 10.5.5.0/24, which is > 10.5.5.96/27. Are you saying that I can't use the address 10.5.5.96 > since it's the 'all zeroes' address? > > > > Nate > Yes, you can't. The "network" and "broadcast" adresses are reserved - you can't use them for IP adresses for physical interfaces. I assure you - there is no way and it should not be done. Sander.