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Date: Tue, 06 Mar 2007 09:29:55 -0600
From: Scott Oertel <freebsd@scottevil.com>
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To: Gary Kline <kline@tao.thought.org>
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Cc: FreeBSD Mailing List <freebsd-questions@freebsd.org>
Subject: Re: awk question
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Gary Kline wrote:
> 	Guys,
>
> 	Having found $9 , how do I /bin/rm it (using system()--yes??)
> 	in an awk one-liner?
>
> 	I'm trying to remove from packages from long ago and find and
> 	print them with
>
> 	ls -lt | awk '{if ($8 == 2006) print $9}';
>
> 	but what I want to remove the file pointed at by $9.  I've tried
> 	FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
> 	What's the magic here?
>
> 	thanks in advance,
>
> 	gary
>
>
>
>   

Another way is:

ls -lt | awk '{if ($8 == 2006) print "rm -rf "$9}' | sh

but I agree, using pkg_delete would be safer:

ls -lt | awk '{if ($8 == 2006) print "pkg_delete "$9}' | sh

-SO