From owner-freebsd-questions  Tue Dec  3  2:42:16 2002
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Date: Tue, 3 Dec 2002 11:42:05 +0100 (MET)
From: Paul Everlund <tdv94ped@cs.umu.se>
To: Roman Neuhauser <neuhauser@bellavista.cz>
Cc: Malik =?iso-8859-2?Q?B=FClent?= <bmalik@ihlas.net.tr>,
	<questions@freebsd.org>
Subject: Re: is there a "replace command" ?
In-Reply-To: <20021203103346.GG56031@freepuppy.bellavista.cz>
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On Tue, 3 Dec 2002, Roman Neuhauser wrote:

> # tdv94ped@cs.umu.se / 2002-12-03 11:13:39 +0100:
> > On Tue, 3 Dec 2002, Malik Bülent wrote:
> > > But my expression has "/" that is there is a "/" in a expression
> > > What shall i do ?
> > > my expression is "new: 11"  I want to change "new: 11"  with "new/11"
> > >
> > > thanks
> >
> > # echo "new: 11" | sed s/new\:\ 11/new\\/11/
>
>     you don't have to use slashes for the delimiters. see sed(1).
>
>     roman@freepuppy ~ 1003:0 > echo "new: 11" | sed 's,: ,/,'
>     new/11
>     roman@freepuppy ~ 1004:0 > echo "new: 11" | sed 's:\: :/:'
>     new/11
>     roman@freepuppy ~ 1005:0 > echo "new: 11" | sed 's-: -/-'
>     new/11

Thanks for the tip! I wasn't aware of that. When it comes to man sed(1):
Reading a Kafka book is light weight reading compared to that man
page. :-)

Best regards,
Paul


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