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Date:      Tue, 19 Feb 2019 23:08:26 +0000
From:      bugzilla-noreply@freebsd.org
To:        fs@FreeBSD.org
Subject:   [Bug 230260] [FUSE] [PERFORMANCE]: Performance issue (I/O block size)
Message-ID:  <bug-230260-3630-07Xk0mKV8n@https.bugs.freebsd.org/bugzilla/>
In-Reply-To: <bug-230260-3630@https.bugs.freebsd.org/bugzilla/>
References:  <bug-230260-3630@https.bugs.freebsd.org/bugzilla/>

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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=3D230260

--- Comment #10 from Conrad Meyer <cem@freebsd.org> ---
(In reply to Kenneth D. Merry from comment #9)
Hi Ken,

I'm having some trouble understanding your reproduction steps.  This is ins=
ide
an LTFS mount?

1. You read 1GB of /dev/zero in 1MB chunks and write it to foo;
2. ls -l foo reports the expected 1GB size;
3. reading foo with a 1MB request size returns 64k, and unexpected end of f=
ile.

I'm really curious how this change breaks LTFS, given a 4k iosize "works."

Thanks!

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