Date: Mon, 20 Nov 2000 08:31:13 -0800 (PST) From: Richard Hodges <rh@matriplex.com> To: Alex Koshterek <havoc@lookanswer.com> Cc: freebsd-hackers@FreeBSD.ORG Subject: Re: Byte order? Message-ID: <Pine.BSF.4.10.10011200827300.52841-100000@mail.matriplex.com> In-Reply-To: <00112017175200.47740@pro.lookanswer.com>
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On Mon, 20 Nov 2000, Alex Koshterek wrote:
> I know, that x86 is big endian architecture
> but simple programm like this:
>
> #include <stdio.h>
> #include <sys/param.h>
> main () {
> /* Are we little or big endian? From Harbison&Steele. */
> union
> {
> long l;
> char c[sizeof (long)];
> } u;
> u.l = 1;
> printf ("Little endian? %s\n", (u.c[sizeof (long) - 1] == 1) ? "yes" : "no");
> #if BYTE_ORDER == BIG_ENDIAN
> printf("Big endian\n");
> #elif BYTE_ORDER == LITTLE_ENDIAN
> printf("Little endian\n");
> #else
> printf("Unknown\n");
> #endif
> }
Just to be different, why not use something like:
if(htonl(1) == 1)
bigendian
else
littleendian
Of course, that spoils the fun of figuring out what the
compiler is doing with the union :-)
All the best,
-Richard
-------------------------------------------
Richard Hodges | Matriplex, inc.
<title> | 769 Basque Way
rh@matriplex.com | Carson City, NV 89706
775-886-6477 | www.matriplex.com
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