Date: Thu, 27 Sep 2001 18:29:26 -0400 From: Kutulu <kutulu@kutulu.org> To: Mike Porter <mupi@mknet.org> Cc: swear@blarg.net (Gary W. Swearingen), freebsd-stable@FreeBSD.ORG Subject: Re: 127/8 continued Message-ID: <5.1.0.14.0.20010927182433.00a27510@127.0.0.1> In-Reply-To: <200109272225.f8RMPLH02946@c1828785-a.saltlk1.ut.home.com> References: <4cd74ctsac.74c@localhost.localdomain> <20010924094048.X5906-100000@coredump.scriptkiddie.org> <200109271411.f8REBNH02164@c1828785-a.saltlk1.ut.home.com> <4cd74ctsac.74c@localhost.localdomain>
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At 04:25 PM 09/27/2001 -0600, Mike Porter wrote: >OK, then I was wrong. The broadcast is (normally) the last address in the >subnet (.255 for a class C, .255 for my subnet ( with a .128 netmask, but I >am in the top half. I presume that those with IP's below .129 have .127 set >for a broadcast, with .128 being the other unusable address. I forget >exactly what its for?) The two reserved addresses are the network address and the broadcast address. The network address is all host bits zero, and the broadcast address is all host bits 1. Thus, for a network of 192.168.0.0 with a netmask of 255.255.255.128, there would be two subnets: 192.168.0.0 <network address> - 192.168.0.127 <broadcast address> 192.168.0.128 <network address> - 192.168.0.255 <broadcast address> The exact math is a pair of pretty basic bitwise functions, which most any networking essentials book will have in it, but that's the general idea. But now we're really getting off the subject of freebsd-stable. :) --K To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-stable" in the body of the message
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