Date: Sat, 13 Jul 2013 18:30:35 +0800 From: "Alex V. Petrov" <alexvpetrov@gmail.com> To: Sergey Kandaurov <pluknet@gmail.com>, stable@freebsd.org Subject: Re: ls -U don't work? Message-ID: <2813184.tAUhP2F1j4@alex.super> In-Reply-To: <CAE-mSO%2BNO1WR_hMKOzmPW8TEmpuv64XVNxmoeLR3a1iFdyEo5g@mail.gmail.com> References: <8704004.oreYQuEkVL@alex.super> <CAE-mSO%2BNO1WR_hMKOzmPW8TEmpuv64XVNxmoeLR3a1iFdyEo5g@mail.gmail.com>
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В письме от 13 июля 2013 13:45:30 Вы написали: > 2013/7/13 Alex V. Petrov <alexvpetrov@gmail.com>: > > subj: > > ls -Ul > > So, what's the problem? Looking at code, > I'd suggest to try adding -t to actually enable sorting, > otherwise it just prints dates but not sorts. > > > total 0 > > -rw-r--r-- 1 alex alex 0 13 июл 15:26 000 > > -rw-r--r-- 1 alex alex 0 13 июл 15:25 111 > > -rw-r--r-- 1 alex alex 0 13 июл 15:25 222 > > -rw-r--r-- 1 alex alex 0 13 июл 15:25 333 > > -t enables sorting (by modified date by default), > -U further specifies to sort by birth time. What is the meaning of '-U'?I thought '-U' = '-tr' man ls: "-U Use time when file was created for sorting or printing." ----- Alex V. Petrov
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