Date: Tue, 23 Aug 2005 11:57:52 +0300 From: Ruslan Ermilov <ru@freebsd.org> To: vladone <vladone@spaingsm.com> Cc: freebsd-ipfw@freebsd.org, freebsd-questions@freebsd.org Subject: Re: error when use table option with ipfw Message-ID: <20050823085752.GB15272@ip.net.ua> In-Reply-To: <163971811.20050823111033@spaingsm.com> References: <163971811.20050823111033@spaingsm.com>
next in thread | previous in thread | raw e-mail | index | archive | help
--7ZAtKRhVyVSsbBD2
Content-Type: text/plain; charset=us-ascii
Content-Disposition: inline
Content-Transfer-Encoding: quoted-printable
On Tue, Aug 23, 2005 at 11:10:33AM +0300, vladone wrote:
> Hi!
> I try to use table option but not work.
> First, i use Freebsd 5.4 release.
> In short i have:
> cmd=3D"ipfw -q"
>=20
> $cmd table 1 add 192.168.0.0/24
> $cmd table 1 add 192.168.2.0/24
> $cmd table 1 add 192.168.3.0/24
> $cmd table 1 add 192.168.4.0/24
>=20
> $cmd add 700 count ip from table(1) to any via $lif
>=20
> When i run the script i receive an error about syntax error "ipfw.sh: 78:=
Syntax error: "(" unexpected".
> I dont understand where is error?
> Need some compiler options to work with this option?
> If i give:
> #ipfw table 1 list
> i have list of entries in this table without any error.
>=20
Since this is a shell script, `(' has a special meaning to group
commands for executing them in a sub-shell. To cancel a special
meaning, you can prefix it with the `\' character.
Cheers,
--=20
Ruslan Ermilov
ru@FreeBSD.org
FreeBSD committer
--7ZAtKRhVyVSsbBD2
Content-Type: application/pgp-signature
Content-Disposition: inline
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.4.1 (FreeBSD)
iD8DBQFDCuUQqRfpzJluFF4RAt6iAKCRsnyObepoH8h1n/hnHtH0KiI+ZgCgirBN
sglnsbu3begX+BYcONr0VD4=
=s+FK
-----END PGP SIGNATURE-----
--7ZAtKRhVyVSsbBD2--
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20050823085752.GB15272>