From owner-freebsd-questions  Mon Oct  8 21:49:31 2001
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From: "Pietralla, Siegfried P" <siegfried.pietralla@eds.com>
To: "'BSD Freak'" <bsd-freak@mbox.com.au>,
	FreeBSD Questions <freebsd-questions@FreeBSD.ORG>
Subject: RE: Outputing a specific line number to standard output
Date: Tue, 9 Oct 2001 14:49:00 +1000 
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hi there,

two simple ways:

using awk:

$ awk 'NR==54{print;exit}' myfile.txt

using head and tail:

$ tail +54 myfile.txt | head -1

regards,
siegfried.

-----Original Message-----
From: BSD Freak [mailto:bsd-freak@mbox.com.au]
Sent: Tuesday, 9 October 2001 14:30
To: FreeBSD Questions
Subject: Outputing a specific line number to standard output


Hi all,

I feel stupid asking this but I have looked in the man page for grep,
sort , cat, head and cut and have not been able to find the answer. 

How do I output to standard output a particular line number in a text file? 

For example say I want to display line 54 in the file myfile.txt . How
do I do this?


Thanks in advance.....

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