Date: Tue, 28 Jun 2011 12:37:19 -0700 From: Josh Carroll <josh.carroll@gmail.com> To: Yuri <yuri@rawbw.com> Cc: freebsd-hackers@freebsd.org Subject: Re: How can process in STOP state consume 200% CPU? Message-ID: <BANLkTinFfyVJVFybjzwq43t3tFE4mm-7cw@mail.gmail.com> In-Reply-To: <4E0A201D.9000601@rawbw.com> References: <4E0A201D.9000601@rawbw.com>
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On Tue, Jun 28, 2011 at 11:40 AM, Yuri <yuri@rawbw.com> wrote: > I got VirtualBox process in a strange state. It has the status STOP but > shows by top as consuming 200% CPU for a very long time. > How is this possible and what does this mean? Process time stays at 0:00 > TIME. kill -9 doesn't kill it. > > PID USERNAME THR PRI NICE SIZE RES STATE C TIME CPU > COMMAND > 9390 yuri 3 44 0 508M 246M STOP 3 0:00 200.00% > VirtualBox Can you send the output of these various procstat commands: procstat -kk 9390 procstat -f 9390 procstat -t 9390 procstat -i 9390 | grep -vE -- '---$' procstat -j 9390 | grep -vE -- '--$' As well as ps output for the process: ps auwwx | grep -w 9390 Also ktrace'ing the process and sending a kdump (or part of it) could be useful. Thanks, Josh
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