Date: Thu, 07 Feb 2019 23:01:32 +0000 From: bugzilla-noreply@freebsd.org To: bugs@FreeBSD.org Subject: [Bug 235589] sh(1): LINENO is always 0 in shell arithmetic Message-ID: <bug-235589-227@https.bugs.freebsd.org/bugzilla/>
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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=3D235589 Bug ID: 235589 Summary: sh(1): LINENO is always 0 in shell arithmetic Product: Base System Version: 12.0-STABLE Hardware: Any OS: Any Status: New Severity: Affects Some People Priority: --- Component: bin Assignee: bugs@FreeBSD.org Reporter: mcdutchie@hotmail.com In sh(1), the LINENO variable (currently executed line number) is always ze= ro when it is read as part of a shell arithmetic expression. For instance: $ echo $LINENO $((LINENO)) $(($LINENO)) 108 0 108 Expected: 3 times "108" (or whatever the current line number is) Note that $(($LINENO)) does work because it expands LINENO as a normal shell expansion before invoking the arithmetic subsystem. However, $((LINENO)) sh= ould be equivalent as it is for all other variables. Another manifestation of the bug is: $ set -u $ echo $((LINENO)) -sh: arithmetic expression: variable not set: "LINENO" --=20 You are receiving this mail because: You are the assignee for the bug.=
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