Date: Wed, 02 Nov 2011 13:35:28 -0700 From: Doug Barton <dougb@FreeBSD.org> To: Mark Saad <nonesuch@longcount.org> Cc: freebsd-hackers@freebsd.org Subject: Re: What is going on with ash / sh Message-ID: <4EB1A990.7080001@FreeBSD.org> In-Reply-To: <CAMXt9NYcO4JsZRUr_TVzoE08F7hyED4EUM5RBH2w6gC5_NSe5Q@mail.gmail.com> References: <CAMXt9NYcO4JsZRUr_TVzoE08F7hyED4EUM5RBH2w6gC5_NSe5Q@mail.gmail.com>
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On 11/02/2011 13:28, Mark Saad wrote: > Hackers > What is going on here, if I run the following shell script, what is > the expected output . The script is named xxx > > #!/bin/sh > ps -ax | grep -v grep | grep xxx > > Here is what I see > > > # sh xxx > 88318 p0 S+ 0:00.00 sh xxx > 88320 p0 R+ 0:00.00 sh xxx > 88321 p0 R+ 0:00.00 sh xxx > > > Can someone explain this ? I only see one. What happens if you run this on the command line? -- "We could put the whole Internet into a book." "Too practical." Breadth of IT experience, and depth of knowledge in the DNS. Yours for the right price. :) http://SupersetSolutions.com/
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