Date: Wed, 24 Oct 2007 00:52:08 +0200 From: cpghost <cpghost@cordula.ws> To: Bruce Cran <bruce@cran.org.uk> Cc: freebsd-questions@freebsd.org, Harald Schmalzbauer <h.schmalzbauer@omnisec.de> Subject: Re: Mentor for C self study wanted Message-ID: <20071024005208.0a8048e4@epia-2.farid-hajji.net> In-Reply-To: <471E7778.4060909@cran.org.uk> References: <200710232044.53240.h.schmalzbauer@omnisec.de> <20071023220134.3abd635e@epia-2.farid-hajji.net> <20071023162454.93851854.wmoran@potentialtech.com> <200710232324.09851.h.schmalzbauer@omnisec.de> <20071024002649.6cc41512@epia-2.farid-hajji.net> <471E7778.4060909@cran.org.uk>
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On Tue, 23 Oct 2007 23:36:40 +0100
Bruce Cran <bruce@cran.org.uk> wrote:
> cpghost wrote:
>
> > There's a mismatch here: scanf("%d", ...) expects a pointer to int,
> > while &nnote is a pointer to a short. Normally, an int occupies more
> > bytes in memory than a short (typically sizeof(int) == 4 on 32bit
> > platforms, and sizeof(int) == 8 on 64bit platforms; while typically
> > sizeof(short) == 2).
>
> I think short and int stay the same on both 32 and 64 bit platforms,
> while it's only long that gets bumped to 8 bytes. At least that
> seems to be what happens on FreeBSD amd64.
Hmmm... yep, you're right, I'm wrong! I've switched compilers
too often recently. Yes, on gcc sizeof(int) == 4 on both 32bit and
64bit. Thanks for pointing this out: I stay corrected. ;)
--
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