Date: Tue, 20 Nov 2007 11:10:29 -0800 (PST) From: White Hat <pigskin_referee@yahoo.com> To: FreeBSD Users Questions <freebsd-questions@freebsd.org> Subject: Storing variable in Bash Message-ID: <542256.58741.qm@web34409.mail.mud.yahoo.com>
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I am attempting to write a script that will work on files stored in an array. The function is supposed to strip the files extension and then store the name of the file as a variable. This is what I have so far.
#!/usr/local/bin/bash
declare -a fname
declare -i count
declare -i limit
fname=( `ls *.sh | tr '\n' ' '` )
count=${#fname[*]}
limit=0
while [ ${limit} -lt ${count} ]; do
echo ${fname[$limit]} | sed -e ``/.sh/s///''
# do something here
limit=$((limit+1))
done
What I want to do is store the file in a variable. I have tried this:
F_Name=echo ${fname[$limit]} | sed -e ``/.sh/s///''
As well as:
F_Name=( `echo ${fname[$limit]} | sed -e ``/.sh/s///''` )
along with several different variants of it, but without success. I continually receive an error message. Due to a particular situation, I cannot use 'basename' to accomplish this task.
Is there anyway that this can be done?
Thanks!
--
White Hat
pigskin_referee@yahoo.com
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