Date: Wed, 24 May 2006 07:12:18 +0530 From: "Joseph Koshy" <joseph.koshy@gmail.com> To: "gs_stoller@juno.com" <gs_stoller@juno.com> Cc: freebsd-hackers@freebsd.org Subject: Re: The 'ln -s' command Message-ID: <84dead720605231842y4fc8f1c9x69bdce897fb470f7@mail.gmail.com> In-Reply-To: <20060523.182218.19235.1026225@webmail29.nyc.untd.com> References: <20060523.182218.19235.1026225@webmail29.nyc.untd.com>
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> I tried the 'ln -s' command in bothe 4.3 & 4.7 in a > situation where it should fail and it did, but it still had > a return/exit code of 0 , I think it should have been > nonzero. I tried 'ln -s a b' where the file b existed > (and was a directory) and I wanted to create the file named > a also pointing to it. The correct form was 'ln -s b a'. > FreeBSD 4.3-RELEASE FreeBSD 4.3-RELEASE #0: Sat Apr 21 \ 10:54:49 GMT 2001 \ jkh@narf.osd.bsdi.com:/usr/src/sys/compile/GENERIC i386 > FreeBSD 4.7-RELEASE FreeBSD 4.7-RELEASE #0: Wed Oct 9 \ 15:08:34 GMT 2002 \ root@builder.freebsdmall.com:/usr/obj/usr/src/sys/GENERIC \ i386 I don't have a 4.3 or 4.7 box, but on 4.11 I see: $ ls a.out a.out $ ln -s foo a.out ln: a.out: File exists $ echo $? 1 Are you really running /bin/ln? Do you run other programs at the time of displaying your PS1 prompt? -- FreeBSD Developer, http://people.freebsd.org/~jkoshy
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