From owner-freebsd-questions@FreeBSD.ORG Tue Apr 25 21:36:59 2006 Return-Path: X-Original-To: freebsd-questions@freebsd.org Delivered-To: freebsd-questions@freebsd.org Received: from mx1.FreeBSD.org (mx1.freebsd.org [216.136.204.125]) by hub.freebsd.org (Postfix) with ESMTP id A536216A400 for ; Tue, 25 Apr 2006 21:36:59 +0000 (UTC) (envelope-from kapiltj@yahoo.com) Received: from web81110.mail.mud.yahoo.com (web81110.mail.mud.yahoo.com [68.142.199.102]) by mx1.FreeBSD.org (Postfix) with SMTP id 2C30543D46 for ; Tue, 25 Apr 2006 21:36:59 +0000 (GMT) (envelope-from kapiltj@yahoo.com) Received: (qmail 24943 invoked by uid 60001); 25 Apr 2006 21:35:54 -0000 DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=s1024; d=yahoo.com; h=Message-ID:Received:Date:From:Subject:To:MIME-Version:Content-Type:Content-Transfer-Encoding; b=MGTmeXSjLsRq2DgfPxRe7DXJ/mECzhPeWaHvOnJevIdt2LUOpltBfQTGRvP9qSi3kTKFMRTVUrA/J81V3IqlLsgrLSPG0hTIqrfJ/Jw+JpRLhI8QYB9mU7tkf+g6oXSlqY+bnbwIMkBYJBTFgCmIM3ZMK2dB0CwgTsw32Z2zcV4= ; Message-ID: <20060425213554.24941.qmail@web81110.mail.mud.yahoo.com> Received: from [66.129.224.36] by web81110.mail.mud.yahoo.com via HTTP; Tue, 25 Apr 2006 14:35:54 PDT Date: Tue, 25 Apr 2006 14:35:54 -0700 (PDT) From: kapil jain To: freebsd-questions@freebsd.org MIME-Version: 1.0 X-Mailman-Approved-At: Tue, 25 Apr 2006 21:44:06 +0000 Content-Type: text/plain; charset=iso-8859-1 Content-Transfer-Encoding: 8bit X-Content-Filtered-By: Mailman/MimeDel 2.1.5 Subject: top on freebsd and wired memory X-BeenThere: freebsd-questions@freebsd.org X-Mailman-Version: 2.1.5 Precedence: list List-Id: User questions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Tue, 25 Apr 2006 21:36:59 -0000 Hi, I have a question, top on freebsd displays active, inactive and wired memory. Since kernel memory has to be non-pageable isn't it that user process resident memory should be active + inactive? However I see some discrepancy. For eg. active is 34M, inactive 116M. top -s 100 gives me resident sizes of all processes, if I sum them up it comes to about 75M. So where is the rest of 116+34-75 = 75M? thanks kapil