Date: Thu, 01 Feb 2007 02:24:00 +0100 From: Karol Kwiatkowski <karol.kwiat@gmail.com> To: Glenn Gillis <glenn@elaw.org> Cc: freebsd-questions@freebsd.org Subject: Re: Obtaining a pid or process owner from netstat? Message-ID: <45C14130.1040502@gmail.com> In-Reply-To: <45C1381F.7010308@elaw.org> References: <45C1381F.7010308@elaw.org>
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[-- Attachment #1 --] Glenn Gillis wrote: > If 'netstat -anp tcp' shows me an IP address and port with a process > listening on it, can anyone suggest a way to determine either the pid or > the owner of the process that is bound to that address? > > In other words: > > % netstat -anp tcp | grep LISTEN > tcp4 0 0 64.112.226.133.8091 *.* LISTEN > tcp4 0 0 64.112.226.133.8090 *.* LISTEN > tcp4 0 0 *.8021 *.* LISTEN > tcp4 0 0 *.8080 *.* LISTEN > tcp4 0 0 64.112.226.141.8080 *.* LISTEN > tcp4 0 0 64.112.226.133.13080 *.* LISTEN > > I'm interested in what is listening on 64.112.226.141.8080, mainly > because I need something else to listen there. I know it's a Zope > instance, but I can't tell *which* Zope instance (there are many on this > box.) > > NB: This is on a 4.11-RELEASE-p26 box. Have a look at sockstat(1) and its options (like '-4' '-l' and '-p'). HTH, Karol -- Karol Kwiatkowski <karol.kwiat at gmail dot com> OpenPGP 0x06E09309 [-- Attachment #2 --] -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.6 (FreeBSD) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iD8DBQFFwUE5ezeoPAwGIYsRCMNLAJ9dYXrJQFSfZjj+ecqsz7EFZ1jbKwCfc98+ euR3jbtbBWopEGNC/kJ9Tf4= =5+gZ -----END PGP SIGNATURE-----
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