From owner-freebsd-hackers  Fri Nov  8 23:27:18 1996
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Date: Sat, 9 Nov 1996 18:22:36 +1100
From: Bruce Evans <bde@zeta.org.au>
Message-Id: <199611090722.SAA00055@godzilla.zeta.org.au>
To: amir@comtrol.com, erich@lodgenet.com
Subject: Re: timeout() function
Cc: hackers@freebsd.org
Sender: owner-hackers@freebsd.org
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>ticks are 1/100 sec, so with a timeout of 1, your function will be

Ticks are 1/hz second.  hz just happens to be 100 in standard
configurations.  Drivers should not assume this.

See timeout(9).

Bruce