Date: Sun, 28 Sep 1997 08:36:19 +0200 From: j@uriah.heep.sax.de (J Wunsch) To: hackers@FreeBSD.ORG Subject: Re: Timeout for sh(1) 'read' ?? Message-ID: <19970928083619.EN11505@uriah.heep.sax.de> In-Reply-To: <199709280603.PAA04849@word.smith.net.au>; from Mike Smith on Sep 28, 1997 15:33:13 %2B0930 References: <19970928073430.CC50911@uriah.heep.sax.de> <199709280603.PAA04849@word.smith.net.au>
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As Mike Smith wrote:
> > $foo=${foo:-default}
>
> Hmm. Actually, you would get the desired behaviour with
>
> val=${default}
Well, sure. I didn't see this. :) You need to assign a value in the
first place anyway.
> read -t 5 val
>
> because read won't have had a chance to modify 'val' if it does time
> out. So should read return an error if it times out? What does ksh do?
It does:
j@uriah 66% ksh93
$ read -t 5 foo # and just wait
$ echo $?
1
$ read -t 5 foo
babble
$ echo $?
0
$ exit
--
cheers, J"org
joerg_wunsch@uriah.heep.sax.de -- http://www.sax.de/~joerg/ -- NIC: JW11-RIPE
Never trust an operating system you don't have sources for. ;-)
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