Date: Wed, 11 Feb 2009 05:31:09 -0600 From: eculp@casasponti.net To: freebsd-questions@freebsd.org Subject: Re: sh parameter substitution problem Message-ID: <20090211053109.17qwm4xcvypwc4gww@intranet.casasponti.net> In-Reply-To: <20090211213011.C38905@sola.nimnet.asn.au> References: <20090211213011.C38905@sola.nimnet.asn.au>
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Quoting Ian Smith <smithi@nimnet.asn.au>:
> I'm getting nowhere trying to parse out IP addresses from strings of
> this form in /bin/sh, which have been awk'd out of 'tail named.run':
>
> addr='195.68.176.4#1440:'
> addr='195.68.176.4#16811:'
> addr='195.68.176.4#276:'
>
> sh(1) in hand, I've tried:
>
> ip=${addr:%#*}
> ip=${addr:%%#*}
> ip=${addr:%[#]*}
> ip=${addr:%%[#]*}
>
> but all of these report './testbit: 7: Syntax error: Bad substitution'
>
> How can I split these strings to exclude the '#' and all beyond,
> preferably using sh syntax, at least without resorting to perl?
sed would work. Something like
for i in addr='195.68.176.4#1440:' addr='195.68.176.4#16811:'
addr='195.68.176.4#276:'
do
echo $i | sed 's/#.*//'
done
of course using the echo line in your script or something similar.
I'm sure there are many simple or simpler solutions.
ed
>
> Please cc me as I'm only subscribed to the digest.
>
> TIA, Ian
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