Date: Wed, 11 Feb 2009 22:46:24 +1100 (EST) From: Ian Smith <smithi@nimnet.asn.au> To: Giorgos Keramidas <keramida@ceid.upatras.gr> Cc: questions@freebsd.org Subject: Re: sh parameter substitution problem Message-ID: <20090211224120.F38905@sola.nimnet.asn.au> In-Reply-To: <87ljsdusk3.fsf@kobe.laptop> References: <20090211213011.C38905@sola.nimnet.asn.au> <87ljsdusk3.fsf@kobe.laptop>
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On Wed, 11 Feb 2009, Giorgos Keramidas wrote:
> On Wed, 11 Feb 2009 21:47:17 +1100 (EST), Ian Smith <smithi@nimnet.asn.au> wrote:
> > I'm getting nowhere trying to parse out IP addresses from strings of
> > this form in /bin/sh, which have been awk'd out of 'tail named.run':
> >
> > addr='195.68.176.4#1440:'
> > addr='195.68.176.4#16811:'
> > addr='195.68.176.4#276:'
> >
> > sh(1) in hand, I've tried:
> >
> > ip=${addr:%#*}
> > ip=${addr:%%#*}
> > ip=${addr:%[#]*}
> > ip=${addr:%%[#]*}
> >
> > but all of these report './testbit: 7: Syntax error: Bad substitution'
> >
> > How can I split these strings to exclude the '#' and all beyond,
> > preferably using sh syntax, at least without resorting to perl?
>
> Remove the ':' part and quote the text to avoid parsing '#' as a comment
> delimiter:
>
> $ addr='195.68.176.4#1440:'
> $ echo "${addr%#*}"
> 195.68.176.4
Thankyou Giorgos,
just before yours arrived I'd twigged that the ':' was wrong there, and
tried ip=${addr%#*} which worked fine. I guess # within ${..} doesn't
get taken as a comment .. which makes sense or these would always need
to be double-quoted.
cheers, Ian
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