Date: Mon, 14 Jul 2003 11:04:54 -0500 From: D J Hawkey Jr <hawkeyd@visi.com> To: Rob <listone@deathbeforedecaf.net> Cc: questions at FreeBSD <freebsd-questions@freebsd.org> Subject: Re: sed(1) regular expression gurus Message-ID: <20030714160454.GA28042@sheol.localdomain> In-Reply-To: <00b001c34a1b$4ad17800$a4b826cb@goo> References: <20030714140816.GA27439@sheol.localdomain> <00b001c34a1b$4ad17800$a4b826cb@goo>
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On Jul 15, at 12:49 AM, Rob wrote:
>
> awk --posix -F'[^0-9A-Za-z.]+' '
> $1 ~ /by/ { result = $2
> for (i=3; i<=NF; i++) {
> if ($i ~ /^([0-9]+\.){3}[0-9]+$/) {
> result = result " " $i
> }
> }
> print result
> }'
>
> There may be 'neater' ways of doing it, but it's the most concise
> example I could come up with.
This is better than anything I've dreamed up with sed or awk, and is
really close, but it fails on this:
by nospam.mc.mpls.visi.com (8.11.6/8.11.6.2) with ESMTP id 3A4E07B03
The parenthetical is a [hacked] sendmail version. I don't see how the
script fails, though, as you do test for a full/complete "dotted quad",
and even test for a BOL and EOL on either side it. The "8.11.6" shouldn't
match. I changed the '+'es to "{1,3}"s for even better precision in the
"if (...)", but it didn't make any difference (nor should it have).
BTW, why the "one or more" flag in the FS assignment?
> You need to include the --posix option to get the '{3}' notation to work
> (peculiar to GNU awk).
Kinda throws portability out the window, but I'll settle for it.
Dave
--
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