Date: Mon, 11 Aug 2003 17:22:07 -0500 From: Dan Nelson <dnelson@allantgroup.com> To: Matthew Graybosch <matthew@starbreaker.net> Cc: FreeBSD Questions <freebsd-questions@freebsd.org> Subject: Re: A little Bash script to help you. Message-ID: <20030811222207.GB37571@dan.emsphone.com> In-Reply-To: <1060639888.14212.35.camel@christabel.starbreaker.net> References: <3F380F5D.6020904@rbcmail.ru> <1060639888.14212.35.camel@christabel.starbreaker.net>
next in thread | previous in thread | raw e-mail | index | archive | help
In the last episode (Aug 11), Matthew Graybosch said: > On Mon, 2003-08-11 at 17:49, Constantine wrote: > > I am writing a script, which involves unzipping some files. I would > > have to unzip 4 different zip-files from some directory, and I > > would need to unzip them to the directory, which would have the > > same name in it as the original zip-file, i.e. I would like to run > > something like "ls *.zip", have each file name recorded in some > > variable, and do a loop like "unzip > > $filename[$i] -d $filename[$i].unzipped/". Can someone help me with the > > code? How can I put the results of a command to a variable? > > The following assumes you have the bash port installed. Just change > the ARCHIVE_DIR variable to the full path of the directory in which > you have your zip files. Make sure to save this code to a file in > "~/bin". I suggest pasting the following code into "~/bin/munzip.sh". Note that this script runs just fine with /bin/sh, so you don't need bash. -- Dan Nelson dnelson@allantgroup.com
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20030811222207.GB37571>