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Date:      Fri, 8 Jun 2001 20:43:08 +0100
From:      Graham Barr <gbarr@pobox.com>
To:        Bernd Walter <ticso@mail.cicely.de>
Cc:        Matt Dillon <dillon@earth.backplane.com>, freebsd-hackers@FreeBSD.ORG
Subject:   Re: read(2) and ETIMEDOUT
Message-ID:  <20010608204308.S50444@pobox.com>
In-Reply-To: <20010608213915.A27537@cicely20.cicely.de>; from ticso@mail.cicely.de on Fri, Jun 08, 2001 at 09:39:15PM %2B0200
References:  <20010607171501.S50444@pobox.com> <200106071653.f57Grsn73369@earth.backplane.com> <20010607180011.U50444@pobox.com> <200106071733.f57HXov74249@earth.backplane.com> <20010607183535.X50444@pobox.com> <200106072220.f57MKwv78170@earth.backplane.com> <20010608213915.A27537@cicely20.cicely.de>

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On Fri, Jun 08, 2001 at 09:39:15PM +0200, Bernd Walter wrote:
> On Thu, Jun 07, 2001 at 03:20:58PM -0700, Matt Dillon wrote:
> > 
> > :
> > :On Thu, Jun 07, 2001 at 10:33:50AM -0700, Matt Dillon wrote:
> > :> 
> > :> :
> > :> :Thanks, I will try setting errno, but I don't think it is signals.
> > :> :I have been running truss on the process. The relevant part is
> > :> :
> > :> :gettimeofday(0xbfbffa54,0x0)                     = 0 (0x0)
> > :> :select(0x50,0x93f8c90,0x0,0x0,0xbfbffa74)        = 3 (0x3)
> > :> :read(0x16,0xa2da000,0x8000)                      ERR#60 'Operation timed out'
> > :> :
> > :> :In fact there are no signals in the whole truss output
> > :> :
> > :> :Graham.
> > :> 
> > :>     What type of descriptor is the read being performed on?  A TCP
> > :>     connection or, say, a reading a file over NFS?  
> > :
> > :It is a TCP/IP connection.
> > :
> > :Graham.
> > 
> >     You can get this if the TCP connection times out, either through a
> >     keepalive timeout or the protocol hits the maximum number of transmit
> >     retries.  I'd have to delve into the cvs logs to see when it was added,
> >     but it seems reasonable.  You should treat it simply as an EIO or
> >     something like that.
> 
> Keepalives are a good point.
> I know of OS/2 Systems that can't handle them and behave the way you
> describe.
> What system is on the other side?

All the systems are exactly the same

Graham.

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