Date: 08 Feb 2002 11:30:20 +0000 From: Gilad Rom <rom_glsa@ein-hashofet.co.il> To: Giorgos Keramidas <keramida@ceid.upatras.gr> Cc: Brett Jackson <brett@bsduser.ca>, questions@FreeBSD.ORG Subject: Re: using `date` in a script Message-ID: <1013167823.247.7.camel@dhcp-251.meshek.eh> In-Reply-To: <20020208025959.GA24241@hades.hell.gr> References: <20020207120404.O7616-100000@bsduser.ca> <20020208025959.GA24241@hades.hell.gr>
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Hi,
Use something like this:
bday=`date '+%m/%d/%Y'`
echo $bday
Gilad
On Fri, 2002-02-08 at 02:59, Giorgos Keramidas wrote:
> On 2002-02-07 12:07, Brett Jackson wrote:
> > Hi,
> >
> > I am having difficulty passing a variable to date(8) and have it spit out
> > the data in the date format.
> >
> > for example:
> > birthday=19450104
> >
> > >date -f ccyymmdd $birthday
> >
> > that is some ugly psuedocode, eh? Can I even do this?
> > I have read the manpage to see how to format the current date, but am lost
> > somewhere when trying the above.
>
> Try the following:
>
> $ date -j -f '%Y%m%d' 19450104 '+%c'
> Thu Jan 4 04:51:50 1945
>
> Note the use of options:
> -j (do not set date, but only print it).
> -f 'input-format' input-date
> and '+%c' to define output format.
>
> --
> Giorgos Keramidas . . . . . . . . . keramida@{ceid.upatras.gr,freebsd.org}
> FreeBSD Documentation Project . . . http://www.freebsd.org/docproj/
> FreeBSD: The power to serve . . . . http://www.freebsd.org/
>
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