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Date:      Tue, 10 Jun 2003 13:00:41 -0700
From:      Sean Chittenden <sean@chittenden.org>
To:        Malcolm Kay <malcolm.kay@internode.on.net>
Cc:        questions@freebsd.org
Subject:   Re: gcc me harder: -Wconversion bug?
Message-ID:  <20030610200041.GR65470@perrin.int.nxad.com>
In-Reply-To: <200306101928.30765.malcolm.kay@internode.on.net>
References:  <20030609230324.GL65470@perrin.int.nxad.com> <200306101825.33674.malcolm.kay@internode.on.net> <20030610092129.GP65470@perrin.int.nxad.com> <200306101928.30765.malcolm.kay@internode.on.net>

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> > > It seems to me that this is doing exactly what is claimed for
> > > -Wconversion. To quote from the gcc man page:
> > >        -Wconversion
> > >               Warn  if  a prototype causes a type conversion that
> > >               is different from what would happen to the same ar-
> > >               gument  in  the  absence  of a prototype.  ...
> > >
> > > Now in the absence of a prototype for f() the argument true would be
> > > promoted from char/bool to int before being passed to the
> > > function. With the prototype in scope it is not promoted. Different
> > > argument widths so warning delivered.
> >
> > % cpp test.c
> > # 1 "test7.c"
> > # 1 "<built-in>"
> > # 1 "<command line>"
> > # 1 "test7.c"
> > # 1 "test7.h" 1
> > # 13 "test7.h"
> > void f(char b);
> > # 2 "test7.c" 2
> >
> > int
> > main(int argc, char *argv[]) {
> >   f((((char)1)));
> >
> >   return(0);
> > }
> >
> > void
> > f(char b) {
> > }
> >
> > Am I missing something that says that there isn't the prototype of
> > the same width?  Last time I checked my vision, f(char b) was the
> > same as f(char b)...  :-/ or am I missing something?  I believe
> > that gcc's promoting the char to an int or to some other non-1
> > byte width data type... but I'm not seeing how, where, or why.
> > -sc
> 
> According to the man page we are comaring what does happen with the
> prototype in scope with what would have happened if the prototype
> was not there.
> 
> You are aware theat the rules of C require that in the absence of a
> prototype actual integer calling arguments of less width than int
> (usually char and short) must be promoted to int before the call?

Wow, that's a really worthless warning.  I had to re-read it in the AM
to fully appreciate its non-usefulness for properly written software.
Thanks... when reading the error message and skimming the man page, I
thought it was promoting width of the argument to 4 bytes, not that
"in the event that the prototype isn't here, things will get hard to
debug."  Thank you, for your incite.  -sc

-- 
Sean Chittenden



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