Date: Thu, 24 Jun 2010 09:14:39 -0700 From: Chip Camden <sterling@camdensoftware.com> To: freebsd-questions@freebsd.org Subject: Re: .sh check for numeric content Message-ID: <20100624161439.GD557@libertas.local.camdensoftware.com> In-Reply-To: <20100624050832.06ef2a46@scorpio> References: <4C22B3D7.6070102@comclark.com> <20100624033257.2D074BEA6@kev.msw.wpafb.af.mil> <20100624050832.06ef2a46@scorpio>
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On Jun 24 05:08, Jerry wrote:
> On Wed, 23 Jun 2010 23:32:57 -0400 (EDT)
> Karl Vogel <vogelke+unix@pobox.com> articulated:
>
>
> > >> On Thu, 24 Jun 2010 09:24:39 +0800,
> > >> Aiza <aiza21@comclark.com> said:
> >
> > A> Receiving a variable from the command line that is suppose to
> > A> contain numeric values. How do I code a test to verify the
> > A> content is numeric?
> >
> > The script below will work with the Bourne or Korn shell.
> > Results for "0 1 12 1234 .12 1.234 12.3 1a a1":
> >
> > 0 is numeric
> > 1 is numeric
> > 12 is numeric
> > 1234 is numeric
> > .12 is numeric
> > 1.234 is numeric
> > 12.3 is numeric
> > 1a is NOT numeric
> > a1 is NOT numeric
>
> I had used this snippet in a script to test for numeric input. It was
> part of a function in a Bash script.
>
> case "${1}" in
> [[:digit:]] )
> IS_DIGIT=1
> ;;
> * )
> IS_DIGIT=0
> printf "\n\a\t *****WARNING*****
> \tYou must enter a digit\n\n"
> ;;
> esac
That [[:digit:]] pattern only works if your shell supports POSIX
character classes in the case statement.
>
> --
> Jerry ???
> FreeBSD.user@seibercom.net
>
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> Please do not ignore the Reply-To header.
> __________________________________________________________________
>
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> when there are so many stupid users?
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--
Sterling (Chip) Camden
http://camdensoftware.com | http://chipstips.com | http://chipsquips.com
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