Date: Tue, 25 Jan 2005 22:06:39 -0800 From: Chris Pressey <cpressey@catseye.mine.nu> To: freebsd-ports@freebsd.org Subject: Re: FreeBSD Port: qmail-1.03_3 Message-ID: <20050125220639.2a83e7ed.cpressey@catseye.mine.nu> In-Reply-To: <41F72FBD.2040906@camber-thrust.net> References: <41F6F431.6060005@tenebras.com> <1106704507.16118.14.camel@shumai.marcuscom.com> <41F72FBD.2040906@camber-thrust.net>
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On Tue, 25 Jan 2005 21:50:53 -0800
Michael Sierchio <ducatista@camber-thrust.net> wrote:
> Joe Marcus Clarke wrote:
>
> >>- while ((k > i) && (cmds.s[k - 1] == ' ') || (cmds.s[k - 1] == '\t'))
>
> > Actually, if k is less than or equal to i and cmds.s[k-1] is a tab, then
> > the first bit of code evaluates to true
>
> if k is less than or equal to i, none of the rest of the statements
> are evaluated.
Wow, then GCC must be REALLY REALLY broken! Observe:
int a(int x)
{
printf("evaluating a\n");
return x;
}
int b(int x)
{
printf("evaluating b\n");
return x;
}
int c(int x)
{
printf("evaluating c\n");
return x;
}
int main()
{
printf("a(0) && b(5) || c(5) result: %d\n", a(0) && b(5) || c(5));
printf("a(1) && b(5) || c(5) result: %d\n", a(1) && b(5) || c(5));
}
-------[ output ]------
evaluating a
evaluating c
a(0) && b(5) || c(5) result: 1
evaluating a
evaluating b
a(1) && b(5) || c(5) result: 1
-------[ output ]------
> They don't make C programmers like they used to!
You can say that again!
-Chris
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