Date: Mon, 20 Jul 2009 10:02:23 -0400 From: Glen Barber <glen.j.barber@gmail.com> To: Lowell Gilbert <freebsd-stable-local@be-well.ilk.org> Cc: stable@freebsd.org Subject: Re: Shell execution ( [was] Re: Value of $? lost in the beginning of a function.) Message-ID: <4ad871310907200702q6d13a44bqaeb2242d65866b16@mail.gmail.com> In-Reply-To: <44tz17k46h.fsf@lowell-desk.lan> References: <4ad871310907191717g1ed90be7y92250f2addc38d43@mail.gmail.com> <44tz17k46h.fsf@lowell-desk.lan>
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Hi, Lowell On Mon, Jul 20, 2009 at 7:02 AM, Lowell Gilbert<freebsd-stable-local@be-well.ilk.org> wrote: > Glen Barber <glen.j.barber@gmail.com> writes: > >> Possibly off-topic... >> >> >> 2009/7/19 Glen Barber <glen.j.barber@gmail.com>: >>> 2009/7/19 Romain Tarti=E8re <romain@blogreen.org>: >>>> Hi Glen, >>>> >>>> On Sun, Jul 19, 2009 at 04:32:28PM -0400, Glen Barber wrote: >>>>> > % sh foo.sh >>>>> > % zsh foo.sh >>>>> > % bash foo.sh >>>>> What happens if you replace '#!/bin/sh' with '#!/usr/local/bin/zsh' ? >>>> >>>> This is not related to my problem since I am not running the script >>>> using ./foo.sh but directly using the proper shell. =A0sh just behaves >>>> differently, that looks odd so I would like to know if it is a bug in = sh >>>> or if there is no specification for this and the behaviour depends of >>>> the implementation of each shell, in which case I have to tweak the >>>> script I am porting to avoid this construct (passing $? as an argument >>>> for example). >>>> >>>> Romain >>>> >>> >>> My understanding was this: >>> >>> If you specify 'sh foo.sh' at the shell, the script will be run in a >>> /bin/sh shell, _unless_ you override the shell _in_ the script. >>> >>> Ie, 'sh foo.sh' containing '#!/bin/sh' being redundant, but 'zsh >>> foo.sh' containing '#!/bin/sh' would execute using zsh. >>> >>> >> >> I meant to say in the last line: "'#!/bin/sh' would override the 'zsh' s= hell." >> >> Can someone enlighten me if I am wrong about this? > > The person to whom you were responding had it closer. > > The shell specified in the "#!" first line is only consulted if you run > it as "./foo.sh". =A0Otherwise, it's input to the shell that you started, > and the line is only a comment. > I suppose that makes sense, but what if the script location is in the user's $PATH? --=20 Glen Barber
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