Date: Sat, 7 May 2011 07:11:28 +0400 From: Yuri Pankov <yuri.pankov@gmail.com> To: Rolf Nielsen <listreader@lazlarlyricon.com> Cc: FreeBSD <freebsd-questions@freebsd.org> Subject: Re: Comparing two lists [SOLVED (at least it looks like that)] Message-ID: <20110507031128.GC1222@procyon.xvoid.org> In-Reply-To: <4DC4AD2C.30307@lazlarlyricon.com> References: <4DC48DB6.8030907@lazlarlyricon.com> <4DC4AD2C.30307@lazlarlyricon.com>
next in thread | previous in thread | raw e-mail | index | archive | help
On Sat, May 07, 2011 at 04:23:40AM +0200, Rolf Nielsen wrote: > 2011-05-07 02:09, Rolf Nielsen skrev: > > Hello all, > > > > I have two text files, quite extensive ones. They have some lines in > > common and some lines are unique to one of the files. The lines that do > > exist in both files are not necessarily in the same location. Now I need > > to compare the files and output a list of lines that exist in both > > files. Is there a simple way to do this? diff? awk? sed? cmp? Or a > > combination of two or more of them? > > > > TIA, > > > > Rolf > > sort file1 file2 | uniq -d I very seriously doubt that this line does what you want... $ printf "a\na\na\nb\n" > file1; printf "c\nc\nb\n" > file2; sort file1 file2 | uniq -d a b c Try this instead (probably bloated): sort < file1 | uniq | tr -s '\n' '\0' | xargs -0 -I % grep -Fx % file2 | sort | uniq There is comm(1), of course, but it expects files to be already sorted. HTH, Yuri
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20110507031128.GC1222>