Date: Fri, 16 Apr 2004 17:17:50 +0100 From: Matthew Seaman <m.seaman@infracaninophile.co.uk> To: JJB <Barbish3@adelphia.net> Cc: "freebsd-questions@FreeBSD. ORG" <freebsd-questions@freebsd.org> Subject: Re: timezone command Message-ID: <20040416161750.GA33400@happy-idiot-talk.infracaninophile.co.uk> In-Reply-To: <MIEPLLIBMLEEABPDBIEGGEBBFMAA.Barbish3@adelphia.net> References: <20040416050053.GA52342@falcon.midgard.homeip.net> <MIEPLLIBMLEEABPDBIEGGEBBFMAA.Barbish3@adelphia.net>
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On Fri, Apr 16, 2004 at 11:48:11AM -0400, JJB wrote:
> Yes that is close enough for an starting point, thank you.
>=20
> I need $timezone to hold the time zone in this format -00:00
> The command date +%z will give it as -0000
>=20
> I know nothing about writing perl scripts.
>=20
> Can somebody show me how to add the : in the output
> of the date command in the simple following script?
>=20
> The cat statement is just so I can see results are correct.
>=20
>=20
> #!/usr/bin/perl
> $timezone=3Ddate +%z;
> cat $timezone
You can do it very easily with perl:
#!/usr/bin/perl -w
use POSIX (strftime);
($d =3D strftime("%z", localtime)) =3D~ s/(\d\d)(\d\d)/$1:$2/;
print "$d\n";
but it's probably a bit too heavyweight to use perl to format the
string if you aren't already writing a whole script in perl. Instead,
try:
date +%z | sed -e 's,\([0-9][0-9]\)\([0-9][0-9]\),\1:\2,'
Cheers,
Matthew
--=20
Dr Matthew J Seaman MA, D.Phil. 26 The Paddocks
Savill Way
PGP: http://www.infracaninophile.co.uk/pgpkey Marlow
Tel: +44 1628 476614 Bucks., SL7 1TH UK
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