Date: Tue, 21 Mar 2017 09:43:31 +0100 From: "Marin Bernard" <lists@olivarim.com> To: "Kristof Provost" <kristof@sigsegv.be> Cc: freebsd-pf@freebsd.org Subject: Re: Support for the enc(4) pseudo-interface Message-ID: <1490085811-bc1aa9c7b83aeddb9dee198bc4071b35@olivarim.com>
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Hi, Thanks for answering. Yes, I know that pf accepts rules mentioning inexistent= =20 interfaces. What puzzles me here is that my ruleset is actually working.=20 With peer0 =3D 1.2.3.4 and peer1 =3D 5.6.7.8, the following ruleset works as= =20 expected: ----- peers =3D "{1.2.3.4, 5.6.7.8}" set skip on lo block all # Allow IKE pass=C2=A0 in proto {tcp, udp} from $peers to self=C2=A0=C2=A0 port isakmp pass out proto {tcp, udp} from self=C2=A0=C2=A0 to $peers port isakmp # Allow ICMPv4 echo requests only through IPsec pass in on enc0 proto icmp from $peers to self icmp-type echoreq ----- If there is no SA, it is impossible for a peer to ping another. As soon as IKE creates a SA, however, ping starts working. As you can see, the last rule is explicitely bound to the inexistent enc0 interface, and yet is working fine. Thanks, Marin. 21 mars 2017 03:30 "Kristof Provost" a =C3=A9crit: > On 20 Mar 2017, at 23:08, Marin Bernard wrote:=20 > > Yet, it appears that pf is able to handle references to enc(4) in its= =20 > > ruleset=20 > > even if the kernel does not support it. Is it expected behaviour? Is=20 > > it=20 > > safe to use such a configuration on a production machine ?=20 > >=20 > pf accepts rules for interfaces that don=E2=80=99t exist (yet), so this is= =20 > expected,=20 > but it won=E2=80=99t do what you want it to do.=20 >=20 > Regards,=20 > Kristof=20
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