Date: Sun, 9 Nov 1997 14:37:48 +0000 From: James Raynard <fhackers@jraynard.demon.co.uk> To: Joerg Wunsch <joerg_wunsch@uriah.heep.sax.de> Cc: freebsd-hackers@freebsd.org Subject: Re: Why doesn't /bin/echo use getopt? Message-ID: <19971109143748.29900@jraynard.demon.co.uk> In-Reply-To: <19971109115007.JB56482@uriah.heep.sax.de>; from J Wunsch on Sun, Nov 09, 1997 at 11:50:07AM %2B0100 References: <25358.879002601@axl.iafrica.com> <19971108175832.31362@jraynard.demon.co.uk> <19971109115007.JB56482@uriah.heep.sax.de>
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On Sun, Nov 09, 1997 at 11:50:07AM +0100, J Wunsch wrote: > As James Raynard wrote: > > Tough question: how do you echo a "-n\n" then (without using > printf(1), of course)? <quote> The only tricky case is echoing -n followed by a newline: $ echo -n '-n > ' -n $ It's ugly, but it works, and this is a rare situation anyway. </quote> [The Unix Programming Environment, Kernighan and Pike] -- In theory, theory is better than practice. In practice, it isn't. James Raynard, Edinburgh, Scotland. http://www.freebsd.org/~jraynard/
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