Date: Sun, 10 Jan 1999 11:56:07 -0800 (PST) From: Andrew Sherrod <ixkatl@yahoo.com> To: questions@FreeBSD.ORG Subject: Need help with wd.c Message-ID: <19990110195607.19765.rocketmail@send101.yahoomail.com>
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Okay, I need a hard-drive guru to help me figure something out.
I had a number of problems getting FBSD to recognize the actual size
of my hard drives. (Eventually I fell back on the old hack of adding a
DOS partition and then deleting it once the geometry was recognized.)
To start: Hardware: Tyan Trinity motherboard with AMD K6-2 350
processor. LBA activated. (Hard drive data to follow).
Running 2.2.8 Free BSD only. No other operating systems.
Okay...
Here is "dmesg | grep wd" :
wdc0 at 0x1f0-0x1f7irq 14 on isa
wdco: unit 0 (wd0): <QUANTUM FIREBALL SE8.4A>
wd0: 8063MB (16514064 sectors), 16383 cyls, 16 heads, 63 S/T 512 B/S
wdc0: unit 1 (wd1): <WDCAC33100H>
wd1: 2014MB (4124736 sectors), 4092 cyls, 16 heads, 63 S/T, 512 B/S
wdc1 at 0x170-0x177 irq 15on isa
wdc1: unit 0(wd2): <Maxtor 84320D4>
wdc2: 1888MB (3866940 sectors), 4092 cyls, 15 heads, 63 S/T, 512 B/s
[omitting CDROM info, as it is irrelevant]
The first size is correct. The second is actually 3016 MB. The third
is 4112MB.
I added the following code to wd.c and recompiled the kernel:
printf("%d:LBA Size: %lu - Read as %lu sectors\n",
lunit,
du->dk_params.wdp_lbasize,
du->dk_dd.d_secperunit);
As I understand the code, if the drive reports an LBA size, this
should be used as the sectors per unit. However, after recompiling
"dmesg | grep LBA" gives:
0:LBA Size: 16514064 - Read as 16514064 sectors
1:LBA Size: 6185088 - Read as 4124736 sectors
2:LBA Size: 8439184 - Read as 3866940 sectors
The first is right. The next two make no sense to me.
Can anyone help explain this?
Andrew Sherrod
(I don't follow questions@FreeBSD.org, so please cc my email address
with the answer...)
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