Date: Fri, 03 Mar 2000 08:49:16 -0800 From: Kuzak <kuzak@kuzak.net> To: EKR <ekr@rtfm.com> Cc: freebsd-stable@FreeBSD.ORG Subject: Re: Password Length Message-ID: <200003031700.e23H0Wp41410@alpha.dgweb.com> In-Reply-To: <kjvh34caok.fsf@romeo.rtfm.com> References: <Kuzak's message of "Fri, 03 Mar 2000 00:08:40 -0800"> <38BF10BF.86D1EA83@duwde.com.br> <Pine.BSF.4.10.10003021939150.15588-100000@tetron02.tetronsoftware.com> <38BF10BF.86D1EA83@duwde.com.br> <200003030819.e238Jjp32583@alpha.dgweb.com>
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>Passwords are ASCII, so the total number of 8-byte 8^8=2^64. > >It should be obvious by inspection that 8^8 << 73! >Incidentally, the number of atoms in a glass of water >is on the order of 10^25 >> 8^8. > I see it more like this... 64^8... Assume 64 possible characters to choose from... for the first char in the passwd you have 64 choices, for the second char in the passwd you have 64 choices, and so on 8 times.. So by the multiplication principal you will have a total of 64*64*64*64*64*64*64*64 or 64^8 possible permutations which is >> than 8^8 Though much less than 73! -Aric To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-stable" in the body of the message
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