Date: Tue, 3 Dec 2002 11:33:46 +0100 From: Roman Neuhauser <neuhauser@bellavista.cz> To: Paul Everlund <tdv94ped@cs.umu.se> Cc: Malik =?iso-8859-2?Q?B=FClent?= <bmalik@ihlas.net.tr>, questions@freebsd.org Subject: Re: is there a "replace command" ? Message-ID: <20021203103346.GG56031@freepuppy.bellavista.cz> In-Reply-To: <Pine.GSO.4.44.0212031113070.19346-100000@kvist.cs.umu.se> References: <Pine.GSO.4.44.0212031113070.19346-100000@kvist.cs.umu.se>
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# tdv94ped@cs.umu.se / 2002-12-03 11:13:39 +0100:
> On Tue, 3 Dec 2002, Malik Bülent wrote:
> > But my expression has "/" that is there is a "/" in a expression
> > What shall i do ?
> > my expression is "new: 11" I want to change "new: 11" with "new/11"
> >
> > thanks
>
> # echo "new: 11" | sed s/new\:\ 11/new\\/11/
you don't have to use slashes for the delimiters. see sed(1).
roman@freepuppy ~ 1003:0 > echo "new: 11" | sed 's,: ,/,'
new/11
roman@freepuppy ~ 1004:0 > echo "new: 11" | sed 's:\: :/:'
new/11
roman@freepuppy ~ 1005:0 > echo "new: 11" | sed 's-: -/-'
new/11
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