Date: Mon, 5 Mar 2007 16:35:06 -0800 From: Gary Kline <kline@tao.thought.org> To: FreeBSD Mailing List <freebsd-questions@FreeBSD.ORG> Subject: awk question Message-ID: <20070306003506.GA12553@thought.org>
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Guys,
Having found $9 , how do I /bin/rm it (using system()--yes??)
in an awk one-liner?
I'm trying to remove from packages from long ago and find and
print them with
ls -lt | awk '{if ($8 == 2006) print $9}';
but what I want to remove the file pointed at by $9. I've tried
FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
What's the magic here?
thanks in advance,
gary
--
Gary Kline kline@thought.org www.thought.org Public Service Unix
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