Date: Thu, 12 Mar 2009 10:25:23 -0400 From: Jerry <gesbbb@yahoo.com> To: freebsd-questions@freebsd.org Subject: Problem with Bash-4 and $(command) syntax Message-ID: <20090312102523.6f5ad248@scorpio>
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[-- Attachment #1 --] I just updated from Bash-3.x to Bash-4.0. There appears to be a problem with the way Bash-4 interprits the following. This works fine on Bash-3.x: <snippet> #!/usr/bin/env bash GET_PATH=1 if $( which gpg2 ); then printf "gpg2 located" fi </snippet> However, under Bash-4, it fail with this error message: ./t.sh: command substitution: line 6: syntax error near unexpected token `)' ./t.sh: command substitution: line 6: ` which gpg2 )' I have several scripts that use the $(command) syntax and they are all failing now. I have replaced that syntax with the older "`" tics method. Is this a known problem with Bash-4? I have not been able to find anything about it on the Bash site. -- Jerry gesbbb@yahoo.com [-- Attachment #2 --] -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.11 (FreeBSD) iEYEARECAAYFAkm5G1sACgkQBvaKIJWWCO2DLwCeIWK5Hn1gnHliPHajtmPBOeUG Dj4An1725D+MLKmmXbX2V4LZll/j5Ne3 =6uLu -----END PGP SIGNATURE-----
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