Date: Thu, 29 Apr 2010 14:18:09 -0400 From: John Baldwin <jhb@freebsd.org> To: freebsd-hackers@freebsd.org Cc: =?utf-8?q?Luk=C3=A1=C5=A1?= Czerner <czerner.lukas@gmail.com> Subject: Re: ioctl, copy string from user Message-ID: <201004291418.09768.jhb@freebsd.org> In-Reply-To: <alpine.DEB.1.10.1004291938210.30007@a04-0215a.kn.vutbr.cz> References: <alpine.DEB.1.10.1004291938210.30007@a04-0215a.kn.vutbr.cz>
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On Thursday 29 April 2010 1:52:45 pm Luk=C3=A1=C5=A1 Czerner wrote: > Hi, >=20 > I know that there are plenty of examples in the kernel code, but I > just can not get it working, so maybe I am doing some stupid mistake > I am not aware of. Please give me a hint if you can. >=20 > What I want to do is simply call the ioctl from the userspace with > (char *) argument. Then, in kernel ioctl handling function copy the > string argument into the kernel space. I have tried it various ways, > everything without any success. >=20 > *** Userspace *** > char name[MAXLEN]; >=20 > strncpy(name, argv[1], MAXLEN); > fprintf(stdout,"Name: %s\n",name); >=20 > if (ioctl(fd, MYIOCTL, name)) { On BSD systems, ioctl() copies the data into the kernel for you ahead of ti= me. =20 What does the definition of MYIOCTL look like? > And the second question. I have commented that I can allocate buffer > dynamically, but I suppose that there will be some locks involved so > I think I can not just use M_WAITOK, am I right ? malloc() and free() acquire their own locks internally, you do not need to= =20 hold any locks to call them. =2D-=20 John Baldwin
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