Date: Wed, 11 Mar 2015 11:26:12 -0700 From: hiren panchasara <hiren@strugglingcoder.info> To: "Simon J. Gerraty" <sjg@juniper.net> Cc: Anuranjan Shukla <anshukla@juniper.net>, "freebsd-arch@freebsd.org" <freebsd-arch@freebsd.org> Subject: Re: Buggy sbspace() on 64bit builds? Message-ID: <20150311182612.GL88380@strugglingcoder.info> In-Reply-To: <5977.1423271024@chaos> References: <D0F95E21.2489D%anshukla@juniper.net> <20150206183036.S1246@besplex.bde.org> <D0FA7C7B.249B1%anshukla@juniper.net> <5977.1423271024@chaos>
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On 02/06/15 at 05:03P, Simon J. Gerraty wrote:
> Anuranjan Shukla <anshukla@juniper.net> wrote:
> > this, along with return value being 'int' acceptable as a final
> > determination?=20
>=20
> It is ok for the function to return long,=20
> so long as an int is used internally.
> Casting the int to long - implicit on return does no harm.
>=20
> #include <stdio.h>
> #include <sys/types.h>
> #include <unistd.h>
>=20
> int
> main(int argc, char *argv[])
> {
> uint a, b;
> long r1;
> int r2;
>=20
> a =3D 1;
> b =3D 2;
>=20
> r1 =3D a - b;
> r2 =3D a - b;
>=20
> printf("r1=3D%ld\nr2=3D%d\nr3=3D%ld\n", r1, r2, (long)r2);
> exit(0);
> }
>=20
> r1=3D4294967295
> r2=3D-1
> r3=3D-1
>=20
> so I think just using 'int' internally should work for now,
> perhaps with a comment saying the object size should match
> those being subtracted etc.
Hi Simon/Anu,
Has this been committed yet? I believe I am running into something
similar in our stable10 build. I am not certain though. In any case,
this should be committed/mfc'd.
Cheers,
Hiren
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