Date: Fri, 27 Dec 2019 13:25:30 -0800 From: Steve Kargl <sgk@troutmask.apl.washington.edu> To: freebsd-current@freebsd.org Subject: OpenSSL breaks factor(6) Message-ID: <20191227212530.GA61314@troutmask.apl.washington.edu>
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The use of OpenSSL in factor(6) breaks factor(6) with respect to its documentation. % man factor ... Numbers may be preceded by a single '+'. ... % factor +125 factor: +125: illegal numeric format. without OpenSSL one gets % factor +125 125: 5 5 5 Although undocumented, factor(6) seems to support hexidecimal input, but does it? % factor abc 2748: 2 2 3 229 % factor 1abc 1: 1 without OpenSSL one gets % factor abc 2748: 2 2 3 229 % factor 1abc 6844: 2 2 29 59 The above behavior with OpenSSL appears to match the following documentation: % man factor ... Numbers are terminated by a non-digit character (such as a newline). except without OpenSSL, factor(6) produces % factor 1abc 6844: 2 2 29 59 where 6844 is the decimal representation of 0x1abc. But, one now finds % factor 1abcp factor: 1abcp: illegal numeric format. so, factor(6) without OpenSSL does not terminate numbers with non-digit characters. -- Steve 20161221 https://www.youtube.com/watch?v=IbCHE-hONow
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