Date: Tue, 14 Sep 1999 20:36:26 -0500 From: Kris Kirby <kris@airnet.net> To: "Kenneth D. Merry" <ken@kdm.org> Cc: scsi@freebsd.org Subject: Re: Reformatting a 520-byte-per-sector drive Message-ID: <37DEF81A.520E2D1B@airnet.net> References: <199909140220.UAA32921@panzer.kdm.org>
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Kenneth D. Merry wrote:
> > > # camcontrol cmd da1 -v -c "1A 0 3 0 c 0" -i 0xc "i1 i1 i1 i1 i1 i3 i1 i3"
> > > 35 0 16 8 1 1052654 0 512
This spits out the appropriate answer.
#root:orgy: {17} camcontrol cmd da0 -v -c "1A 0 3 0 c 0" -i 0xc "i1 i1
i1 i1 i1 i3 i1 i3"
35 0 16 8 0 1931265 0 520
> > > The last 3-byte integer is the block size. So, in theory, I suppose you
> > > could change the blocksize by doing something like this:
> > > # camcontrol cmd da1 -v -c "15 10 0 0 c 0" -o 0xc "b 0 0 8 0 0:i3 0 v:i3" 512
> > > [ of course you'd substitute "da3" for "da1" above ]
This sets it properly, but when chased with a format, doesn't do
anything. (Except format the drive. :-)
> > What would be the proper command to change the number of blocks? Docs
> > say it needs both.
>
> Well, in that case, you'd do this I think:
>
> # camcontrol cmd da3 -v -c "15 10 0 0 c 0" -o 0xc "b 0 0 8 0 v:i3 0 v:i3" xxxx 512
>
> Where the 'xxxx' is the number of 512 byte blocks.
#root:orgy: {15} camcontrol cmd da0 -v -c "15 10 0 0 c 0" -o 0xc "b 0 0
8 0 v:i3 0 v:i3" 1962030 512
camcontrol: error sending command
(pass0:aha0:0:0:0): MODE SELECT(06). CDB: 15 10 0 0 c 0
(pass0:aha0:0:0:0): ILLEGAL REQUEST asc:26,0
(pass0:aha0:0:0:0): Invalid field in parameter list sks:80,0
> To figure out the number of blocks, you'll probably want to look at the
> current dmesg, and find the number of blocks. Then:
I've got the IBM pages, which tell exactly how many blocks.
<http://ssdweb01.storage.ibm.com/techsup/hddtech/0663x/0663xjum.htm>;
--
Kris Kirby
<kris@airnet.net>
-------------------------------------------
TGIFreeBSD... 'Nuff said.
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