Date: Thu, 18 Sep 2003 19:55:36 +0900 From: Rob Lahaye <lahaye@snu.ac.kr> To: Charles Howse <chowse@charter.net>, "'Gil Agno Virtucio'" <gihl@nesic.com.ph>, freebsd-questions@FreeBSD.ORG Subject: Re: randomize execution the a script? Message-ID: <3F698F28.7080902@snu.ac.kr> In-Reply-To: <001701c37dd2$9467f170$04fea8c0@moe> References: <001701c37dd2$9467f170$04fea8c0@moe>
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Charles Howse wrote:
>
> I don't happen to have random installed on my system, however jot is
It's in /usr/games/random of FreeBSD 4.8.
> Won't randomNumber=$? Just return 0 if the previous command completes
> successfully?
> Shouldn't it be:
> randomNumber=`random -e 60`
No. In 'man 6 random', it says:
random [-er] [-f filename] [denominator]
-e If the -e option is specified, random does not read or write any-
thing, and simply exits with a random exit value of 0 to
denominator - 1, inclusive.
So you must capture its exit value for the random number :).
R.
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