Date: Wed, 20 Feb 2002 16:17:57 -0500 From: "B.K. DeLong" <bkdelong@pobox.com> To: questions@freebsd.org Subject: BASH programming question Message-ID: <5.1.0.14.2.20020220160637.02763050@pop.earthlink.net>
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Hey all -
I'm somewhat new to the world of BASH scripting. I'm trying to write a
script that I can throw in cron to check if my IP has changed. However, I'm
having problems with the variable. What I'm trying to say, is "if $IP is
not null then email me"
ie. if diff produces no results, then the IP is the same.
However, I can't quite figure out the way to define this without getting a
"too many arguments" error.
#!/usr/local/bin/bash -x
ifconfig | grep "inet " | cut -f2 -d" " | grep 24. > /.newip
IP='diff /.newip /.currentip'
if [ $IP <> null ]; then
cat /.newip > /.currentip;
mail -s "New IP" bkdelong@pobox.com < /.currentip;
echo "A New IP has been found"
exit 0
fi
Thanks in advance for any tips.
--
B.K. DeLong
bkdelong@pobox.com
617.877.3271
http://www.brain-stream.com Play.
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