Date: Wed, 11 May 2016 14:13:49 -0400 From: "James B. Byrne" <byrnejb@harte-lyne.ca> To: freebsd-questions@freebsd.org Subject: Re: FreeBSD-10.3 root ZFS redux Message-ID: <5845c9cfc3bed4171df9b4b386573782.squirrel@webmail.harte-lyne.ca> In-Reply-To: <0409d2208ccce8e2f9e0ce6526bf6756.squirrel@webmail.harte-lyne.ca> References: <0409d2208ccce8e2f9e0ce6526bf6756.squirrel@webmail.harte-lyne.ca>
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On Wed, May 11, 2016 13:34, James B. Byrne wrote:
> We have eight (8) 3Tbyte drives on a system upon which I am installing
> FreeBSD. The quest arises of whether one should simply grab all of
> the disks or partition them to reserve a spare area. The reason put
> forth for partitioning is this statement in man zspool(8):
>
>
> zpool replace [-f] pool device [new_device]
>
> Replaces old_device with new_device. This is equivalent
> to attaching new_device, waiting for it to resilver, and
> then detaching old_device.
>
> The size of new_device must be greater than or equal to
> the minimum size of all the devices in a mirror or raidz
> configuration.
>
> One can conceive of a 3Tb drive which has slightly more or fewer
> accessible sectors than its nominal size. If the zspool incorporates
> a drive with fewer accessible sectors than average for its nominal
> size and one seeks to replace it with a similar drive that has more
> than average for the same nominal capacity then what is the result?
> Is the new drive accepted or rejected?
>
>
I managed to get this reversed in my head as I composed. The question
is what happens when a nominally 3TB HDD is put in that has fewer
accessible sectors than a similar 3TB drive already present?
--
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